Question

помогите пожалуйста

Answer 1

1)

sin(π - π/6) = sin(π/6) = 0,5;

tg(π/2 + π/4) = - ctg(π/4) = - 1;

sin(π - π/6)*tg(π/2 + π/4) = 0,5*(- 1) = - 0,5

2)

sin(π/2 - π/4) = cos(π/4) = √2/2;

cos(3π/2 - π/4) = - sin(π/4) = - √2/2;

tg(π - π/6) = - tg(π/6) = - √3;

sin(π/2 - π/4)*cos(3π/2 - π/4)*tg(π - π/6) = (√2/2)*(- √2/2)*(- √3) =  √3/2