Question

Помогите с 2-я номерами

Answer 1

$(3+13n)^2=9+78n+169n^2\\\\0,01x^2+3xy+225y^2=(0,1x+15y)^2$

Answer 2

$(3 + 13n) {}^{2} = 9 + 78n + 169n {}^{2} = 169n {}^{2} + 78n + 9 \\ \\ 0.01x {}^{2} + 3xy + 225y {}^{2} = \frac{1}{100} {x}^{2} + 3xy + 225y {}^{2} = ( \frac{1}{10} x + 15y) {}^{2}$