Question

(3a^2-b)^2-(3a^2+b)^2 при a=-1/2,b=-1,5

Answer 1

$(3a^2-b)^2-(3a^2+b)^2=9a^4-6a^2b+b^2-9a^4-6a^2b-b^2=-12a^2b\\\\-12\cdot(-\frac{1}{2})^2\cdot(-1,5)=-12\cdot\frac{1}{4}\cdot(-1,5)=-3\cdot(-1,5)=4,5$