Question

помогите, мне сейчас надо​

Answer 1

$2a)y=\frac{1}{3}x^{2}+3\\\\f(3)=\frac{1}{3}*3^{2}+3=\frac{1}{3}*9+3=3+3=6\\\\f(3)=6\\\\f(-5)=\frac{1}{3}*(-5)^{2}+3=\frac{1}{3}*25+3=\frac{25}{3}+3=8\frac{1}{3}+3=11\frac{1}{3}\\\\f(-5)=11\frac{1}{3} \\\\2b)(k;6)\\\\6=\frac{1}{3}k^{2}+3|*3\\\\18=k^{2} +9\\\\k^{2}=9\\\\k_{1}=-3\\\\k_{2}=3$