Question

ПОМОГИТЕ С ЗАДАНИЕМ​

Answer 1

$\tt\displaystyle \frac{y^2-2}{2y^2-4y\sqrt{2}+4}=\frac{(y-\sqrt{2})(y+\sqrt{2})}{(\sqrt{2}y)^2-2\sqrt{2}y+2^2} =\frac{(y-\sqrt{2})(y+\sqrt{2})}{(\sqrt{2}y-2)^2}=\frac{(y-\sqrt{2})(y+\sqrt{2})}{2(y-\sqrt{2})^2}\\\\=\frac{y+\sqrt{2}}{2(y-\sqrt{2})}$

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