Question

Вычислить:
cosα и tgα, если sinα = 0,6
π:2<α<π

Answer 1

$cos(a) = -\sqrt{1-sin^2(a)}=-\sqrt{0.64}=-0.8\\tg(a) =\frac{sin(a)}{cos(a)}=-\frac{0.6}{0.8} =-0.75$