Question

40 баллов Математика 6 класс,Можете решения в тетради !?​

Answer 1

$13 \frac{7}{12} + 42 \frac{1}{6} {}^{(2} = (13 + 42) + ( \frac{7}{12} + \frac{2}{12} ) = 55 + \frac{9}{12} = 55 + \frac{3}{4} = 55 \frac{3}{4}$

$872 \frac{5}{8} {}^{(9} + 15 \frac{25}{36} {}^{(2} = (872 + 15) + ( \frac{45}{72} + \frac{50}{72} ) = 887 + \frac{95}{72} = 887 + 1 \frac{23}{72} = 888 \frac{23}{72}$

$473 \frac{5}{12} {}^{(7} - 362 \frac{4}{21} {}^{(4} = (473 - 362) + ( \frac{35}{84} - \frac{16}{84} ) = 111 + \frac{19}{84} = 111 \frac{19}{84}$

$55 - 23 \frac{51}{64} = (55 - 23) + ( \frac{51}{64} ) = 32 + \frac{51}{64} = 32 \frac{51}{64}$

$11 \times 4 \frac{17}{31} = 10 \frac{31}{31} \times 4 \frac{17}{31} = \frac{341}{31} \times \frac{141}{31} = \frac{141}{341}$

$52 \frac{2}{3} \div 13 = \frac{158}{3} \div 12 \frac{3}{3} = \frac{158}{3} \div \frac{39}{3} = \frac{158}{3} \times \frac{3}{39} = \frac{158}{39} = 4 \frac{2}{39}$