Question

Вычислите
$(3\sqrt{32}+\sqrt{162}-2\sqrt{288})*\sqrt{2}+15$

Answer 1

$(3\sqrt{32}+\sqrt{162}-2\sqrt{288})*\sqrt{2}+15=(3\sqrt{16*2}+\sqrt{81*2}-2\sqrt{144*2})\sqrt{2}+15=(12\sqrt{2}+9\sqrt{2}-24\sqrt{2})\sqrt{2}+15=(-3\sqrt{2})\sqrt{2}+15=-6+15=9$