Question

(2-3x)(2+3x)=
m^3+n^3=
t^3-64=
(a+4)^3=

Answer 1

Ответ во вложении

Удачи)

Answer 2

$(2-3x)(2+3x)=2^{2}-(3x)^{2}=4-9x^{2};\\m^{3} +n^{3} =(m+n)(m^{2} -mn+n^{2} );\\t^{3} -64=(t-4)(t^{2} +4t+16);\\(a+4)^{3} =a^{3}+12a+48a+24 .$