Question

Уравнение
$sin^{2}x-2=sin2x-cos^{2}x$

Answer 1

sin²x - 2 = sin2x - cos²x

sin²x + cos²x - 2 = sin2x

1 - 2 = sin2x

sin2x = - 1

2x = (-π/2) + 2πn

x = (-π/4) + πn , n ∈ Z

ОТВЕТ: (-π/4) + πn , n ∈ Z