Question

Решите уравнение
a) (x+1)^3-x^2(x+3)+2=0
б) (x-2)^3-x^2(x-6)-4=0

Answer 1

a) (x+1)³-x²(x+3)+2=0;

x³+3x²+3x+1-x³-3x²+2=0;

3x+3=0

x=-1

б)(x-2)³-x²(x-6)-4=0

x²-6x²+12x-8-x³+6x²-4=0

12x-12=0

x=1