Question

Помогите решить уравнение ​

Answer 1

$\tt x^3+6x^2-x-6=0\\x^2(x+6)-(x+6)=0\\(x^2-1)(x+6)=0\\(x-1)(x+1)(x+6)=0\\x=1;x=-1;x=-6$

Ответ: $\sf -6;-1;1$

Answer 2

${x}^{3} + 6 {x}^{2} - x - 6 = 0 \\ x {}^{2} (x + 6) - (x + 6) = 0 \\ x + 6 = 0 \\ x = - 6$

${x}^{2} - 1 = 0 \\ {x}^{2} = 1 \\ x1 = 1 \\ x2 = - 1$