Question

√2 (√50-√32)
помогите пж))

Answer 1

$\displasytyle \tt \sqrt2(\sqrt{50}-\sqrt{32})=\sqrt{50\cdot2}-\sqrt{32\cdot2}=\sqrt{100}-\sqrt{64}=10-8=\boxed{2}$

Answer 2

$\sqrt{2}(\sqrt{50}-\sqrt{32})=\sqrt{2}*\sqrt{50}-\sqrt{2}*\sqrt{32}=\sqrt{100}-\sqrt{64}=\sqrt{10^{2} }-\sqrt{8^{2} }=10-8=2$