Question

$\left \{ {{\frac{5}{x^{2}+xy }+\frac{4}{y^2+xy}=\frac{13}{6} } \atop {\frac{8}{x^{2}+xy}-\frac{1}{y^2+xy} =1}} \right.$
должно получиться (2;1) и (-1;-2)

Answer 1

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