Question

Срочно помогите до 10:00 утра завтра

Answer 1

$\sf\displaystyle 3x^3-2y^3-6x^2y^2+xy=3x^2(x-2y^2)+y(x-2y^2)=(3x^2+y)(x-2y^2);\\x=\frac{2}{3};y=\frac{1}{2}\\\\(3\cdot \frac{4}{9}+\frac{1}{2})(\frac{2}{3}-2\cdot\frac{1}{4})=(\frac{4}{3}+\frac{1}{2})(\frac{2}{3}-\frac{1}{2})=\frac{11}{6}\cdot\frac{1}{6}=\frac{11}{36}$