Question

решить (4  4/9х+3 1/3)х9  1/3х  если х=2 2/5

Answer 1

(4  4/9х+3 1/3)х9+1/3х,  если х=2 2/5

(4  4/9*2 2/5+3 1/3)*9+1/3*2 2/5=(40/9*12/5+10/3)*9+1/3*12/5=(32/3+10/3)*9+4/5=

=42/3*9+4/5=14*9+4/5=126 4/5

 

 

если -1/3х, то

(4  4/9*2 2/5+3 1/3)*9-1/3*2 2/5=(40/9*12/5+10/3)*9-1/3*12/5=(32/3+10/3)*9-4/5=

=42/3*9-4/5=14*9-4/5=126-4/5=125 1/5

 

Answer 2

$(4frac{4}{9x}+3frac{1}{3})cdot9frac{1}{3x}=(frac{40}{9cdot2frac{2}{5}}+frac{10}{3})cdotfrac{28}{3cdot2frac{2}{5}}=$=$(frac{40}{9cdotfrac{12}{5}}+frac{10}{3})cdotfrac{28}{3cdotfrac{12}{5}}= (frac{40cdot5}{9cdot12}+frac{10}{3})cdotfrac{28cdot5}{3cdot12}=(frac{50}{27}+frac{10}{3})cdotfrac{35}{9}=$=$(frac{50+90}{27})cdotfrac{35}{9}=frac{140}{27}cdotfrac{35}{9}=frac{4900}{243}=20frac{40}{243}$