Question

ребят , помогите , пожалуйста ​

Answer 1

$b_{2} =-2*\frac{1}{b_{1} } =-2*(\frac{1}{-6} )=\frac{1}{3} \\\\b_{3} =-2*\frac{1}{b_{2} } =-2*(\frac{1}{\frac{1}{3} } )=-2*3=-6\\\\b_{4} =-2*\frac{1}{b_{3} } =-2*(\frac{1}{-6} )=\frac{1}{3} \\\\b_{5} =-2*\frac{1}{b_{4} } =-2*(\frac{1}{\frac{1}{3} } )=-6$