Question

с р о ч н о
комплексные числа​

Answer 1

$x\in R\; ,\; \; y\in R\\\\z_1=x-\frac{y^2}{i}-4+5i\; \; ,\; \; z_2=y^2+1-3xi\\\\z_1=xi+y^2i-4i-5=(x+y^2-4)\, i-5\\\\z_2=(y^2+1)-3x\, i=-z_1\; \; \to \; \; \left \{ {{y^2+1=4-x-y^2} \atop {-3x=5}} \right. \; \left \{ {{2y^2=3+5/3} \atop {x=-5/3}} \right. \\\\\left \{ {{y^2=\frac{14}{3}} \atop {x=-\frac{5}{3}}} \right. \; \; \left \{ {{y=\pm \sqrt{\frac{14}{3}}} \atop {x=-\frac{5}{3}}} \right.\\\\Otvet:\; \; (-\frac{5}{3}\, ,\, \sqrt{\frac{14}{3}})\; \; ,\; \; (-\frac{5}{3}\, ,\, -\sqrt{\frac{14}{3}})\; .$