Question

Помогите решить,бьюсь несколько дней,

Answer 1

1. a/(2*√a)*x/(2*√x)=(√a/2)*(√x/2)=√(ax)/4=(ax)¹/²/4.

2. (∛(a²/x)*a⁻¹*√x)⁶=(a²/³*x⁻¹/³*a⁻¹*x¹/²)⁶=(a⁻¹/³*x¹/⁶)⁶=a⁻²*x=x/a².

3. ((ax)¹/²/4):(x/a²)=a¹/²*x¹/²*a²/(4*x)=(a⁵/²)/(4*(x¹/²)).

4. ⁻²√((1/4)*a²*√(a/x))=1/√((1/4)*a²*√(a/x))=1/((1/2)*a*a¹/⁴*x⁻¹/⁴)=

=2*(x¹/⁴)/(a⁵/⁴).

5. (a⁵/²)*2*(x¹/⁴)/(4*x¹/²*a⁵/⁴)=(a⁵/⁴)/(2*x¹/⁴)=((a*(⁴√a)/(⁴√x))/2=

=(a/2)*⁴√(a/x).