Question

(4-y)²-y(y+1) при y= -1 дробь 9 или -1/9​

Answer 1

$(4-y)^2-y(y+1)=16-8y+y^2-y^2-y=-9y+16\\\\y=-\frac{1}{9} \\\\-9y+16=-9*(-\frac{1}{9} )+16=1+16=17\\Otvet: 17$