Question

прошу 2,6............​

Answer 1

Пошаговое объяснение:

$\frac{1}{3}\sqrt{18}+2\sqrt{2}= \frac{1}{3}\sqrt{9*2}+2\sqrt{2}=\frac{1}{3}\sqrt{9}*\sqrt{2}+2\sqrt{2}=\\\\=\frac{1}{3}*3*\sqrt{2}+2\sqrt{2}=\sqrt{2}+2\sqrt{2}=3\sqrt{2}$

$3\sqrt{48}-\sqrt{75}+\frac{1}{7}\sqrt{147}=3\sqrt{16*3}-\sqrt{25*3}+\frac{1}{7}\sqrt{49*3}=\\\\=3\sqrt{16}*\sqrt{3}-\sqrt{25}*\sqrt{3}+\frac{1}{7}\sqrt{49}*\sqrt{3}=3*4\sqrt{3}-5\sqrt{3}+\frac{1}{7}*7\sqrt{3}=\\\\=12\sqrt{3}-5\sqrt{3} +\sqrt{3}=7\sqrt{3}+\sqrt{3}=8\sqrt{3}$