Question

разложите на трехчлен $6x^{2}+5x-1$

Answer 1

$6x^2+5x-1=0\\D=25-4*6*(-1)=49\\x1=\frac{-5+7}{12} =\frac{2}{12}=\frac{1}{6} \\ \\x2=\frac{-5-7}{12}=-\frac{12}{12} =-1 \\\\6x^2+5x+1=6(x-\frac{1}{6} )(x+1)$

Answer 2

6x²+5x-1=6(x²+5/6 *x-1/6)=

6(x²+2*5/12 *x+25/144-25/144-1/6)=


6((x+5/12)²-(25+24)/144)=

6(x+5/12-7/12)(x+5/12+7/12)=

6(x-1/6)(x+1)