Question

Решить систему
4 (x+y) -2 (3x-2y) =36
-5 (x-2y) +4 (x+4y) =128

Answer 1

4х+4у-6х+4у=36

-5х+10у+4х+16у=128

-2х+8у=36

-х+26у=128

х-4у=-18

-х+26у=128

22у=110

у=5

х-4*5=-18

х=-18+20

х=2