Предмет: Геометрия, автор: PROSTONIKTO8

Диагональ прямоугольного параллелепипеда с плоскостью основания образует угол 45°, стороны основания равны 15 и 20 см.
Вычисли высоту параллелепипеда.

Ответ: высота равна см, где H=

Ответы

Автор ответа: Аноним

d=(15^2+20^2)^0.5=25

H=25 - как прямоугольный треугольник с углами в основании =45 град

его катеты равны друг другу.

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