Question

-6(2+m)(2-m)+(5-m)^2-m(7m-1)=0

Answer 1

$- 6(4 - {m}^{2} ) +2 5 - 10m + {m}^{2} - 7 {m}^{2} + m = 0 \\ - 24 + 6 {m}^{2} + 25 - 9m - 6 {m}^{2} = 0 \\ 9m = 1 \\ m = \frac{1}{9}$