Question

(х+2)^2-(2х-1)^2=0 помогите решить

Answer 1

${x}^{2} + 4x + 4 - {4x }^{2} + 4x - 1 = 0 \\ 3 {x}^{2} - 8x + 1 = 0 \\ 64 - 12 = 52$