Question

Решите пожалуйста спасибо заранее

Answer 1

$1)a) \frac{x}{y} \\ b) \frac{3}{x + 5}$

В)

$\frac{a}{6(b - 2)} = \frac{a}{6b - 12}$

Г)

$\frac{x - 8}{ {x}^{2} }$

$2)a) \frac{3(a + b)}{5(a + b)} = \frac{3}{5} = 0.6 \\ b) \frac{7(x - 2y)}{3(x - 2y)} = \frac{7}{3} = 2 \frac{1}{3}$

$v) \frac{5(a - 4c)}{15ac} = \frac{a - 4c}{3ac}$

$g) \frac{x - 2b}{x(x - 2b)} = \frac{1}{x}$

$3)a) - \frac{2}{x} \\ b) \frac{3(c - 3d)}{2(3d - c)} = - \frac{3}{2} = - 1.5$

$v) \frac{a(a - 2b)}{3(2b - a)} = - \frac{a}{3} \\ g) \frac{ {m}^{2}(m - 5n) }{ {n}^{2} (5n - m)} = - \frac{ {m}^{2} }{ {n}^{2} }$

4.

$a) \frac{5(x - 2)}{(x - 2)(x + 2)} = \frac{5}{x + 2} \\ b) \frac{(a - 3)(a + 3)}{5(3 + a)} = \frac{a - 3}{5}$

$v) \frac{( x - 2) {}^{2} }{3(x - 2)} = \frac{x - 2}{3}$

Г)

$\frac{(b + 3) {}^{2} }{(b - 3)(b + 3)} = \frac{b + 3}{b - 3}$

5.

А)

$\frac{(y - 4)(y + 4)}{ {y}^{2}(4 - y) } = - \frac{y + 4}{ {y}^{2} }$

Б)

$\frac{(a - 1) {}^{2} }{(1 - a)(1 + a)} = \frac{1 - a}{1 + a}$

В) не знаю

Г) не знаю