Question

Помогите решить задания производные срочно (15 баллов )

Answer 1

$3)f(x)=\frac{3x+2}{2x-1}\\\\f'(x)=\frac{(3x+2)'*(2x-1)-(3x+2)(2x-1)'}{(2x-1)^{2} }=\frac{3(2x-1)-2(3x+2)}{(2x-1)^{2} }=\frac{6x-3-6x-4}{(2x-1)^{2} } =-\frac{7}{(2x-1)^{2} }$

$4)f(x)=(1-6x^{3})^{5}\\\\f'(x)=((1-6x^{3})^{5})'=5(1-6x^{3})^{4}*(1-6x^{3})'=5(1-6x^{3})^{4}*(-18x^{2})=-90x^{2}(1-6x^{3})^{4}$