Question

Помогите!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$6 {x}^{2} - x + 8 = 0 \\ d = 1 - 4 \times6 \times 8 = - 191 \\ \\ 3x - {x}^{2} = 0 \\ x(3 - x) = 0 \\ x1 = 0 \\ x2 = 3 \\ \\ 4 - 36 {a}^{2} = 0 \\ (2 - 6a)(2 + 6a) = 0 \\ a1 = \frac{2}{6} = \frac{1}{3 } \\ a2 = - \frac{1}{3}$
в первом уравнении нет корней Д<0

Answer 2

1) x1=0; x2=7/6

2) x1=0; x2=3

3) a1=-1/3; a2=1/3