Question

1/9х в квадрате-х+2=0

Answer 1

$\frac{1}{9} x {}^{2} - x + 2 = 0 \\ x {}^{2} - 9x + 18 = 0 \\ x {}^{2} - 3x - 6x + 18 = 0 \\ x \times (x - 3) - 6(x - 3) = 0 \\ (x - 3) \times (x - 6) = 0 \\ x - 3 = 0 \\ x - 6 = 0 \\ x = 3 \\ x = 6 \\ x1 = 3 \\ x2 = 6$