Question

ПОМОГИТЕ С АЛГЕБРОЙ РЕШИТЬ УРАВНЕНИЯ СРОЧНО

Answer 1

${x}^{2} + 5x = 0 \\ x \times (x + 5) = 0 \\ x = 0 \\ x = - 5$
$2 {x}^{2} - 3x = 0 \\ x \times (2x - 3) = 0 \\ x = 0 \\ 2x - 3 = 0 \\ x 1= 0 \\ x 2= \frac{3}{2} = 1.5$
$- 7 {x}^{2} + 4x = 0 \\ - x \times (7x - 4) = 0 \\ - x = 0 \\ 7x - 4 = 0 \\ x1 = 0 \\ x2 = \frac{4}{7}$