Question

помогите, пожалуйста!​

Answer 1

1.
$a)3a - 4ax + 2 - 12a + 16ax = \\ - 9a + 12ax + 2$
$b)6 {y}^{6} + 3 {y}^{2}$
2.
$a)5b(2a - b) \\ b)2 {a}^{2} (9a + 8)$
3.
$9x - 6x + 6 = 10 - 5x \\ 3x + 6 = 10 - 5x \\ 3x + 6 - 10 + 5x = 0 \\ 8x - 4 = 0 \\ 8x = 4 \\ x$
$x = 0.5$
5.
$3(3x - 1) - 6x = 2(4 - x) \\ 9x - 3 - 6x = 8 - 2x \\ 3x - 3 = 8 - 2x \\ 3x - 3 - 8 + 2x = 0 \\ 5x - 11 = 0 \\ 5x$
$5x = 11 \\ x = \frac{11}{5} = 2 \frac{1}{5} = 2.2$