Question

помогите пожалуйста решите уравнение (z-2)^3-z^2(z-6)=13z-7 (3-t)^3+3t+21=-t^2(t-9)

Answer 1

1) (z-2)³-z²(z-6)=13z-7

z³-6z²+12z-8-z³+6z²-13z+7=0

12z-13z-8+7=0

-z-1=0

z= -1

2) (3-t)³+3t+21=-t²(t-9)

27-27t+9t²-t³+3t+21= -t³+9t²

27-27t+3t+21=0

-24t+48=0

t= 2

Answer 2

1) (z - 2)³ - z²(z - 6) = 13z - 7

z³ - 3 * z² * 2 + 3 * z * 2² - 2³- z³ + 6z² = 13z - 7

z³ - 6z² + 12z - 8 - z³+ 6z²  - 13z + 7 = 0

- z = 1

z = -1

2) (3 - t)³ + 3t + 21 = - t²(t - 9)

3³ - 3 * 3² * t + 3 * 3 * t² - t³ + 3t + 21 = - t³ + 9t²

27 - 27t + 9t² - t³ + t³ - 9t² + 3t + 21= 0

- 24t = - 48

t = 2