Question

Решите уравнение:
3/x+2-5=4/x-2

Answer 1

$\displaystyle x\neq-2; x\neq 2\\\\ \frac{3}{x+2}-5=\frac{4}{x-2} \\\\\frac{3-5(x+2)}{x+2}=\frac{4}{x-2}\\\\\frac{3-5x-10}{x+2}=\frac{4}{x-2}\\\\(-5x-7)(x-2)=4(x+2)\\\\-5x^2-7x+10x+14=4x+8\\\\-5x^2-x+6=0\\\\5x^2+x-6=0\\\\D=1-4*5*(-6)=1+120=121=11^2\\\\x_{1.2}=\frac{-1 \pm 11}{10}\\\\x_1=-1.2; x_2=1$

Ответ: х=1 или х= -1,2