Question

x^2+36=13x по теореме виета

Answer 1

Квадратное уравнение.

$x^2 + 36 = 13x;\\x^2 - 13x + 36 = 0;\\\\\boxed{\;\begin{array}{c|c}\tt Teope_Ma\;Bue_Ta&x_1+x_2 = -p&\bf x^2 + px + q = 0&x_1\cdot x_2 = q\end{array}\;}\\\\\\\begin{cases}x_1 + x_2 = 13,\\x_1\cdot x_2 = 36;\end{cases}\\x_1 = 4, x_2 = 9.\\\\\tt OTBET: 4; 9.$

Answer 2

$x^{2} -13x+36=0\\x=4\\x=9$