Question

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Answer 1

$\frac{ \sqrt{40} }{ \sqrt{10} } = \sqrt{ \frac{40}{10} } = \sqrt{4} = 2$
$\sqrt{5 \frac{4}{9} \times 11 \frac{14}{25} } = \sqrt{ \frac{49}{9} \times \frac{289}{25} } = \sqrt{ \frac{49}{9} } \times \sqrt{ \frac{289}{25} } = \frac{7}{3} \times \frac{17}{5} = \frac{119}{15} = 7 \frac{14}{15}$
$\sqrt{ \frac{9}{16} \times {5}^{2} } = \frac{3}{4} \times 5 = \frac{15}{4} = 3 \frac{3}{4} = 3.75$
${ (\sqrt{3} )}^{2} \times \sqrt{5} = 3 \sqrt{5}$
$5 \sqrt{3} = \sqrt{25 \times 3} = \sqrt{75}$
$7 \sqrt{2} = \sqrt{49 \times 2} = \sqrt{98}$
$2 \sqrt{5} = \sqrt{4 \times 5} = \sqrt{20}$
$3 \sqrt{7} = \sqrt{9 \times 7} = \sqrt{63}$ [/tex]7 \sqrt{3} + 56 \sqrt{3} - 147 = 2 \sqrt{3} \\ 61 \sqrt{3}= 147[/tex]