Question

8x(1+2x)–(4x+3)(4x–3)=2x. (x–6)^2–x(x+8)=2 9x^2–1–(3x–2)2=0 (x–1)(x+1)=2(x -3)^2–x2.

Answer 1

8x(1+2x)–(4x+3)(4x–3)=2x.

8х+16х^2-16х^2+9=2х

6х=-9

х=-1,5

(x–6)^2–x(x+8)=2

х^2-12х+36-х^2-8х=2

-20х=2-36

-20х=-34

х=1,7

9x^2–1–(3x–2)2=0

9х^2-1-9х^2+12х-4=0

12х=5

х=5/12

(x–1)(x+1)=2(x -3)^2–x2

х^2-1=2х^2-12х+18-х^2

12х=19

х=19/12=1 7/12