Question

Математика производная

Answer 1

$\displaystyle y=\sqrt[4]{x^3}=x^\frac{3}4\\\\y'=\frac{3}4x^{\frac{3}4-1}=\frac{3}4\cdot x^{-\frac{1}4}=\frac{3}4\cdot\frac{1}{x^\frac{1}4}=\frac{3}4\cdot\frac{1}{\sqrt[4]{x}}=\boxed{\frac{3}{4\sqrt[4]{x}}}$