Question

Решить $\sqrt{x} +\sqrt[3]{x} +\frac{1}{x}$

Answer 1

$y=\sqrt x+\sqrt[3]x+\frac1x=x^{\frac12}+x^{\frac13}+x^{-1}\\y'=\frac12x^{-\frac12}+\frac13x^{-\frac23}-x^{-2}=\frac1{2\sqrt x}+\frac1{3\sqrt[3]{x^2}}-\frac1{x^2}$