Question

Решить систему уравнений. Очень срочно!

Answer 1

$\left \{ {{y=1.5x + 3} \atop {y=x^2-4}} \right.\\\\ 1.5x + 3 = x^2 -4\\x^2 - 1.5x - 7 = 0\\\\x= \dfrac{1.5\pm\sqrt{2.25+28}}{2} = \dfrac{1.5\pm 5.5}{2} = \left \{ {{-2} \atop {3.5}} \right. \\\\\\x = - 2, y = 0;\\x = 3.5, y = 8.25$

Ответ: (-2, 0), (3.5, 8.25)