Question

(5у+7х+1)-(3у+4х-2)=2у+2
Уравнение

Answer 1

$(5y+7x+1)-(3y+4x-2)=2y+2\\ 5y+7x+1-3y-4x+2=2y+2\\ 2y+3x+3=2y+2\\ 3x+3=2\\ 3x=-1\\ x=-\frac{1}{3}$

при ЛЮБОМ у ,  $x=-\frac{1}{3}$