Question

4y(y-9)-(y-10) (y+3)

Answer 1

здравствуй.

$4y(y-9)-(y-10)(y+3)=\\=4y^2-36y-(y^2-10y+3y-30)=\\=4y^2-36y-(y^2-7y-30)=\\=4y^2-36y-y^2+7y+30=\\=3y^2-29y+30$

удачи в учебе.

Answer 2

4у(у-9) -(у-10)(у+3) =4у^2-36-(у^2+3у-10у-30) =4у^2-36-у^2-3у+10у+30=3у^2+7у-6