Question

$3^{log_{3} (x+4)}=x^2+2x-26$

Answer 1

ОДЗ :

x + 4 > 0

x > - 4

$3^{log_{3}(x+4) }=x^{2}+2x-26\\\\x+4=x^{2}+2x-26\\\\x^{2}+2x-26-x-4=0\\\\x^{2} +x-30=0\\\\D=1^{2}-4*(-30)=1+120=121=11^{2}\\\\x_{1}=\frac{-1+11}{2}=5\\\\x_{2}=\frac{-1-11}{2}=-6$

Ответ : 5