Question

$log_{0.25}64 + log_{5}125$
Вычислите

Answer 1

$log_{0.25}64 + log_{5}125=log_{\frac{1}{4}}4^3 + log_{5}5^3=log_{\frac{1}{4}}(\frac{1}{4})^{-3} + 3log_{5}5=\\-3log_{\frac{1}{4}}(\frac{1}{4})^{-3} + 3=-3+3=0$