Question

решите уравнения: а) 3х=х+20 б) х/16+1=х/12 в) (х+2)4=(х-2)6 г) х-0,2=320

Answer 1

а)
$3x = x + 20 \\ 2x = 20 \\ x = 10$
б)
$\frac{x}{16} + 1 = \frac{x}{12} \\ \frac{x + 16}{16} = \frac{x}{12} \\ 12x + 192 = 16x \\ 4x = 192 \\ x = 48$
в)
$( x + 2)4 = (x - 2)6 \\ 4x + 8 = 6x - 12 \\ 10x = 20 \\ x = 2$

г)
$x - 0.2 = 320 \\ x = 320 + 0.2 \\ x = 320.2$