Question

Решите уравнение
(5х-1)(х+2)+3(х-4)(х+4)=2(2х+3)^2-8

Answer 1

• 5x^2+10x-x-2+3(x^2-16)=2(4x^2+12x+9)-8
• 5x^2+9x-2+3x^2-48=8x^2+24x+18-8
• 8x^2+9x+46 =8x^2+24x+10
• 24x-9x -46+10=0
• 15x-36=0
• 15x=36
• x=5/12