Question

(х+1)^2-36=0
Решите срочно!!!

Answer 1

(x+1)²-36=0

(x+1)²-6²=0

(x+1-6)*(x+1+6)=0

(x-5)*(x+7)=0

x1=5,       x2= -7

Answer 2

(x+1)²=36
$\sqrt{ {(x + 1)}^{2} } = \sqrt{36}$
±(x+1)=±6
1)x+1=6
x=5
2)x+1=-6
x=-7
3)-x-1=6
x=-7
4)-x-1=-6
x=5
Ответ: x=5;x=-7