Question

Срочно!!!!!!!!!!Даю 50 баллов!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Найди наименьшее значение функции y=−1/7x2+5 на отрезке [−8;7].

Answer 1

(-x)²=x²≥0 , x∈R

(-1/7)x²≤0

(-1/7)x²+5≤5

(-8)²=64, 7²=49

(-1/7)(-8)²+5=(-1/7)(64)+5=-64/7+5=-64/7+35/7=-29/7

y=-29/7, x=-8