Question

Помогите,пожалуйста.
С 1 по 7

Answer 1

1)
$x = \sqrt{ {12}^{2} + {5}^{2} } = 13$
2)
$x = \sqrt{ {10}^{2} - {8}^{2} } = 6$
3)
$x = \sqrt{ {5}^{2} + {1}^{2} } = \sqrt{26}$
$y = \sqrt{ {12}^{2} + {5}^{2} } = 13$
4)
$\sqrt{ {26}^{2} - {10}^{2} } = 24 \\ x = 24 - 8 = 16$
$y = \sqrt{ {10}^{2} + {8}^{2} } = 2 \sqrt{41}$
5)
$x = \sqrt{ {10}^{2} - {8}^{2} } = 6$