Question

Помогите решить уравнение.
20×(1/х+1/х+9)=1
То,что делится, типо дробь.

Answer 1

$20 * \displaystyle(\frac{1}{x} +\frac{1}{x} +9)=1\\\\\\20 * (\frac{1+1+9x}{x} )=1\\\\\\\frac{20(2+9x)}{x} =1\\\\\\\frac{40+180x}{x} =1\\\\\\\frac{40+180x}{x} -1=0\\\\\\\frac{40+180x-x}{x} =0\\\\\\\frac{40+179x}{x} =0\\\\x \neq 0\\\\40 + 179x = 0\\\\179x = -40\\\\x = \displaystyle \frac{-40}{179} =-\frac{40}{179}$